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People who play craps are just crazy over systems,
attempting to combine and match wagers in the hope that they will discover the
enigmatic formula to triumph over the casino.
Sometime or other most systems work, and assuming a player wins a game by using
a system, it goads others to try over and again too. However, eventually the
casino naturally always triumphs over the players.
On receiving systems from readers, the main challenge is not whether it awards
the player an advantage but rather decoding why the system doesn’t award it.
Not long ago, a player named Chuloco sent me a system my email and it goes like
this:
“Assuming a player placed ten dollars on pass, ten dollars on don’t pass, ten
dollars on the field at the same time and continued to do this from the lines
come and don’t come. Isn’t it possible that the player wins or loses the field
on a six, seven or eight? The six or eight would provide the player with fortified
come number while the seven, apart from the field wager, would break even.”
This system incurs a number of weak points. Firstly, don’t pass and pass don’t
quite accurately offset don’t come and come on following rolls. Each pass loser
is don’t lose once you’ve established a point and the reverse also holds true.
Pass losers on a two and three win on the don’t pass, while on the come out don’t
pass losers on seven and eleven on pass win.
Up till now all well and good, however the twelve has to be also be reckoned
with. The twelve does not win on a don’t pass but loses on a pass with the come
out. This type of method produces a loss of ten dollars on a pass and not having
an offset win on a don’t pass because the amount of times that twelve is rolled
is once for every thirty six come out rolls.
The more involved problem is associated with the one roll wager field, maintaining
a house advantage far greater than the 1.4 percent on a don’t pass or a 1.41
percent on a pass; where the house edge is 5.56 percent if twelve gives a payment
of two to one, and 2.78 percent if the twelve gives a payout of three to one.
Thus we place the most expensive bet on the bet’s weakest part if we continue
to feed the field wager.
We shall now examine this system’s results for each rolled number on the come
out where each attempt has a thirty dollar stake. For the time being, the assumption
is that for each attempt there is only one field bet:
- On field with a two to one payout you win twenty dollars; pass offsets don’t
pass. Generally you win twenty dollars that is a two with a single roll of thirty
six.
- On field you win ten dollars; pass offsets don’t pass. Generally you win ten
dollars for a three with two rolls of thirty six, namely a three with twenty
dollars totaling.
- On field you win ten dollars: pass offsets don’t pass. Generally you win ten
dollars for each with three rolls of thirty six, namely a four with thirty dollars
totaling.
- On field you lose ten dollars: pass offsets don’t pass. Generally you lose
ten dollars for each with four rolls of thirty six, namely a five with forty
dollars totaling the loss.
- On field you lose ten dollars: pass offsets don’t pass. Generally you lose
ten dollars for each with five rolls of thirty six, namely a six with fifty dollars
totaling the loss.
- On field you lose ten dollars: pass offsets don’t pass. Generally you lose
ten dollars for each with five rolls of thirty six, namely a seven with sixty
dollars totaling the loss.
- On field you lose ten dollars: pass offsets don’t pass. Generally you lose
ten dollars for each with five rolls of thirty six, namely an eight with fifty
dollars totaling the loss.
- On field you win ten dollars: pass offsets don’t pass. Generally you win ten
dollars for each with four rolls of thirty six, namely a nine with forty dollars
totaling the win.
- On field you win ten dollars: pass offsets don’t pass. Generally you win ten
dollars for each with three rolls of thirty six, namely a nine, with thirty dollars
totaling the win.
- On field you win ten dollars: pass offsets don’t pass. Generally you win ten
dollars for each with two rolls of thirty six, namely an eleven with twenty dollars
totaling the win.
- On field you win two to one twenty dollars payoff or three to one thirty dollars
payoff: on the pass you lose ten dollars and on the don’t pass you break even.
Generally you win ten or twenty dollars for one roll of thirty six, namely a
twelve.
You’ll receive one hundred and seventy or one hundred and eighty dollars winnings
if you total all that on two, three, four, nine, ten, eleven and twelve; however
on five, six, seven and eight you’ll end up losing two hundred dollars. Therefore
the player has losses of twenty or thirty dollars on an thirty six betting series
average, contingent on a twelve field wager payoff.
A house advantage of 2.78 percent results if there is a field payment of a two
to one on a twelve or 1.85 percent if there is a three to one payoff. Whatever
happens, the player spots the house more of an advantage that if the player sticks
to a don’t pass or pass. The encompassing house advantage spans between the lowest
and highest, which was just as anticipated.
If according to Chuloco’s suggestion the player continues to place field wagers
after having established a point, it deteriorates even more. The sequences, some
two thirds of them, beginning with four, five, six, eight, nine or ten, the player
places a minimum of two field wagers and prior to the pass and don’t pass wagers
are resolved could place many more. Increasingly larger sums of money are sunk
into the casino’s side of the table as ever increasing sums are sunk into the
most inferior wager in the combination.
Some other reader sent an email regarding a foolproof money earner system, so
next week we’ll examine that one. |
